1+7/x=8/x^2

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Solution for 1+7/x=8/x^2 equation:


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

7/x+1 = 8/(x^2) // - 8/(x^2)

7/x-(8/(x^2))+1 = 0

7/x-8*x^-2+1 = 0

7*x^-1-8*x^-2+1 = 0

t_1 = x^-1

7*t_1^1-8*t_1^2+1 = 0

7*t_1-8*t_1^2+1 = 0

DELTA = 7^2-(-8*1*4)

DELTA = 81

DELTA > 0

t_1 = (81^(1/2)-7)/(-8*2) or t_1 = (-81^(1/2)-7)/(-8*2)

t_1 = -1/8 or t_1 = 1

t_1 = -1/8

x^-1+1/8 = 0

1*x^-1 = -1/8 // : 1

x^-1 = -1/8

-1 < 0

1/(x^1) = -1/8 // * x^1

1 = -1/8*x^1 // : -1/8

-8 = x^1

x = -8

t_1 = 1

x^-1-1 = 0

1*x^-1 = 1 // : 1

x^-1 = 1

-1 < 0

1/(x^1) = 1 // * x^1

1 = 1*x^1 // : 1

1 = x^1

x = 1

x in { -8, 1 }

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